(4-x)/(x^2+4x-32)

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Solution for (4-x)/(x^2+4x-32) equation: 


D( x )

x^2+4*x-32 = 0

x^2+4*x-32 = 0

x^2+4*x-32 = 0

x^2+4*x-32 = 0

DELTA = 4^2-(-32*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)-4)/(1*2) or x = (-144^(1/2)-4)/(1*2)

x = 4 or x = -8

x in (-oo:-8) U (-8:4) U (4:+oo)

(4-x)/(x^2+4*x-32) = 0

x^2+4*x-32 = 0

x^2+4*x-32 = 0

DELTA = 4^2-(-32*1*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)-4)/(1*2) or x = (-144^(1/2)-4)/(1*2)

x = 4 or x = -8

(x+8)*(x-4) = 0

(4-x)/((x+8)*(x-4)) = 0

4-x = 0 // - 4

-x = -4 // * -1

x = 4

x in { 4} 

x belongs to the empty set

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